Where is San Fernando, The Philippines?
San Fernando is a city found in Central Luzon, The Philippines. It is located 15.03 latitude and 120.69 longitude and it is situated at elevation 6 meters above sea level.
San Fernando has a population of 251,248 making it the 4th biggest city in Central Luzon. It operates on the JST time zone, which means that it follows the same time zone as San Jose del Monte.
Quick facts
Country | The Philippines |
State | Central Luzon |
Population | 251,248 |
Elevation | 6 m over sea level |
Time Zone | JST |
Longitude | 120.689800 |
Latitude | 15.028600 |
This page was last updated on October 15, 2015.